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Recognize to use 2 equations

u_{n}=u_{1}+(n-1)d

12=u_{1}+(5-1)d

12=u_{1}+4d

12-4d=u_{1}- first equation

S_{n}=\frac{n}{2}(2u_{1}+(n-1)d)

60=\frac{6}{2}(2u_{1}+(6-1)d)

20=(2u_{1}+5d)-second equation

Substitute the first equation into the second

20=(2(12-4d)+5d)

20=24-8d+5d

3d=4

d=\frac{4}{3}

Substitute the value of d into the first equation

12=u_{1}+4d

12=u_{1}+4(\frac{4}{3})

u_{1}=\frac{20}{3}

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